HEAT LOSS
The previous experiment has so many variables that it might have been difficult to get accurate results. This experiment will be done under a more controlled environment so it should be easier to collect accurate data. We will be comparing the temperature drops of two different cups of boiling water. One cup will be ceramic and the other will be made of Styrofoam.
Get out your digital thermometer . You could also make good use of a data logger with this experiment.

Take heat loss readings for hot cups of
water. Every minute record the temperature of the cup of water for 30
minuets.
1. A ceramic cup of boiling water.
2. A polystyrene foam cup of boiling water
3. A double polystyrene foam cup of boiling water
4. A polystyrene foam cup of boiling water with lid.
Plot four time vs. temperature graphs for the four heat loss experiments. Which one looses heat fastest. Which one retains it's heat the longest. Why?
Upload your findings to the Bulletin Board. If possible scan your graph and upload these results with the image function of the bulletin board.
HEAT LOSS
1.
What are some factors that contribute to home heating loss?
Low
outside temperature is something we don’t have much control over. Degree days
are used to measure the extent and duration of low outside temperature. They are
the average daily temperature differences between the inside temperature and 650
F.
DEGREE
DAYS are used to determine
how much fuel will be needed to heat a building in a given area. Individual
degree days are calculated by subtracting the average outside temperature from
the 65o F.
2. Calculate the degree days for
All degree days
in which the outside temperature is colder than the inside temperature are added
together to arrive at the annual degree days (DD/year). The temperature
difference between the inside and outside of the building is the primary cause
of heat loss in the winter months. Other factors include insulation, surface
area and air infiltration.
HEAT
LOSS CALCULATIONS
In order to
calculate the annual heat loss of a building we must first know the number of
degree days per year for the area. Next we will have to examine the insulation
factors (U) and the surface areas (A) in question. The following abbreviations
are used in heat loss calculations.
DEGREE DAYS: DD
= (Ti - Ta)/day
HOURLY HEAT LOSS:
Q = U·A·(DD)/hr
YEARLY HEAT LOSS:
E = U·A·(DD)/yr . 24hr
E
Energy needed per year
BTU
Q
Hourly rate of heat loss
(Btu/hr)
U
Heat transfer coefficient
(Btu/hr-ft2-°F) = 1/R
A
Heat transfer area
(ft2)
Ti
Inside design temperature (°F)
(65o standard)
Ta
Outside average temperature
(°F)
DD
Degree Day
(Ti - Ta) °F
3.
Calculate the heating
needs of a simple shed roof house 12 feet wide, 20 feet long and eight foot high
with one 3 X 6 foot air tight door. The average yearly degree days for this
house are 5,000. Do not consider the heat loss from the floor or air
infiltration.
R
for walls
= 5
U =?
R for ceiling
= 10 U
=?
R for door
= 2
U =?
REMEMBER
E = U·A· (DD)/yr.
24hr
E = U·A ·5,000. 24
E = U·A ·120,000
POORLY
INSULATED SHED
|
|
A |
R |
U |
U·A·
(DD)/yr. 24hr |
|
WALLS |
sq
ft |
|
|
BTU |
|
CEILING |
sq
ft |
|
|
BTU |
|
DOOR |
sq
ft |
|
|
BTU |
|
TOTAL |
|
|
|
BTU |
|
GALLONS |
|
|
|
gallons
of oil |
4.
Now
let’s calculate the heat loss for the same shed in the same place after adding
insulation. Let’s give the walls an R factor of 15, the ceiling an R factor of
30 and then let’s add a storm door to give our entry way an R factor of 4.
|
|
A |
R |
U |
U·A·
(DD)/yr. 24hr |
|
WALLS |
sq
ft |
|
|
BTU |
|
CEILING |
sq
ft |
|
|
BTU |
|
DOOR |
sq
ft |
|
|
BTU |
|
TOTAL |
|
|
|
BTU |
|
GALLONS |
|
|
|
gallons
of oil |
Notice
the value of insulation.